Optimal. Leaf size=152 \[ -\frac {2 b \left (11 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{5 d e}+\frac {2 a \left (a^2+2 b^2\right ) \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{d \sqrt {e \cos (c+d x)}}-\frac {6 a b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}{5 d e}-\frac {2 b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2}{5 d e} \]
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Rubi [A]
time = 0.16, antiderivative size = 152, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 5, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {2771, 2941,
2748, 2721, 2720} \begin {gather*} -\frac {2 b \left (11 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{5 d e}+\frac {2 a \left (a^2+2 b^2\right ) \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{d \sqrt {e \cos (c+d x)}}-\frac {2 b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2}{5 d e}-\frac {6 a b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}{5 d e} \end {gather*}
Antiderivative was successfully verified.
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Rule 2720
Rule 2721
Rule 2748
Rule 2771
Rule 2941
Rubi steps
\begin {align*} \int \frac {(a+b \sin (c+d x))^3}{\sqrt {e \cos (c+d x)}} \, dx &=-\frac {2 b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2}{5 d e}+\frac {2}{5} \int \frac {(a+b \sin (c+d x)) \left (\frac {5 a^2}{2}+2 b^2+\frac {9}{2} a b \sin (c+d x)\right )}{\sqrt {e \cos (c+d x)}} \, dx\\ &=-\frac {6 a b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}{5 d e}-\frac {2 b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2}{5 d e}+\frac {4}{15} \int \frac {\frac {15}{4} a \left (a^2+2 b^2\right )+\frac {3}{4} b \left (11 a^2+4 b^2\right ) \sin (c+d x)}{\sqrt {e \cos (c+d x)}} \, dx\\ &=-\frac {2 b \left (11 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{5 d e}-\frac {6 a b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}{5 d e}-\frac {2 b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2}{5 d e}+\left (a \left (a^2+2 b^2\right )\right ) \int \frac {1}{\sqrt {e \cos (c+d x)}} \, dx\\ &=-\frac {2 b \left (11 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{5 d e}-\frac {6 a b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}{5 d e}-\frac {2 b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2}{5 d e}+\frac {\left (a \left (a^2+2 b^2\right ) \sqrt {\cos (c+d x)}\right ) \int \frac {1}{\sqrt {\cos (c+d x)}} \, dx}{\sqrt {e \cos (c+d x)}}\\ &=-\frac {2 b \left (11 a^2+4 b^2\right ) \sqrt {e \cos (c+d x)}}{5 d e}+\frac {2 a \left (a^2+2 b^2\right ) \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )}{d \sqrt {e \cos (c+d x)}}-\frac {6 a b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))}{5 d e}-\frac {2 b \sqrt {e \cos (c+d x)} (a+b \sin (c+d x))^2}{5 d e}\\ \end {align*}
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Mathematica [A]
time = 0.82, size = 94, normalized size = 0.62 \begin {gather*} \frac {10 a \left (a^2+2 b^2\right ) \sqrt {\cos (c+d x)} F\left (\left .\frac {1}{2} (c+d x)\right |2\right )+b \cos (c+d x) \left (-30 a^2-9 b^2+b^2 \cos (2 (c+d x))-10 a b \sin (c+d x)\right )}{5 d \sqrt {e \cos (c+d x)}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 6.06, size = 279, normalized size = 1.84
method | result | size |
default | \(-\frac {2 \left (8 b^{3} \left (\sin ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-20 a \,b^{2} \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{4}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-12 b^{3} \left (\sin ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+5 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, \EllipticF \left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) a^{3}+10 \sqrt {\frac {1}{2}-\frac {\cos \left (d x +c \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-1}\, \EllipticF \left (\cos \left (\frac {d x}{2}+\frac {c}{2}\right ), \sqrt {2}\right ) a \,b^{2}-30 a^{2} b \left (\sin ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+10 a \,b^{2} \cos \left (\frac {d x}{2}+\frac {c}{2}\right ) \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-4 b^{3} \left (\sin ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+15 a^{2} b \sin \left (\frac {d x}{2}+\frac {c}{2}\right )+4 b^{3} \sin \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5 \sin \left (\frac {d x}{2}+\frac {c}{2}\right ) \sqrt {-2 \left (\sin ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right ) e +e}\, d}\) | \(279\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order
4.
time = 0.10, size = 124, normalized size = 0.82 \begin {gather*} -\frac {{\left (5 \, \sqrt {2} {\left (i \, a^{3} + 2 i \, a b^{2}\right )} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) + i \, \sin \left (d x + c\right )\right ) + 5 \, \sqrt {2} {\left (-i \, a^{3} - 2 i \, a b^{2}\right )} {\rm weierstrassPInverse}\left (-4, 0, \cos \left (d x + c\right ) - i \, \sin \left (d x + c\right )\right ) - 2 \, {\left (b^{3} \cos \left (d x + c\right )^{2} - 5 \, a b^{2} \sin \left (d x + c\right ) - 15 \, a^{2} b - 5 \, b^{3}\right )} \sqrt {\cos \left (d x + c\right )}\right )} e^{\left (-\frac {1}{2}\right )}}{5 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {{\left (a+b\,\sin \left (c+d\,x\right )\right )}^3}{\sqrt {e\,\cos \left (c+d\,x\right )}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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